Question

A certain spring has a resting length of 0.08 m (8 cm) when it is not stretched. The spring is stretched to a length of 0.10 m (10 cm), 0.02 m beyond its natural length. Holding it in this stretched position requires a force of 20 N. Question: What is the force function for this spring? Answer: Hooke's Law says that the force required to maintain the spring in a stretched position is the linear function F(x) = kx. Find the spring constant, k, for the spring described above, and enter that number as your final answer.

Answer 1

The spring constant is
`k =1000 \ N/m`

Explanation:

From the question we are told that

The resting length is
`x = 0.08 \ m`

The extension of spring is
`e = 0.02 \ m`

The new length of spring is
`l = 0.10 \ m`

The force is
`F = 20 \ N`

The spring constant is

`k = (F)/(e)`

substituting values

`k = (20)/(0.02)`

`k =1000 \ N/m`