Question

Write the equation of a circle with a center at (-2, 3) and a radius of 4.

(x + 2)^2 + (y - 3)^2 = 4
(x - 2)^2 + (y + 3)^2 = 4
(x - 2)^2 + (y + 3)^2 = 16
(x + 2)^2 + (y - 3)^2 = 16

Answer 1

The equation of a circle:

`(x+2)^2+(y-3)^2 = 16`

Explanation:

The equation of a circle:

`(x-h)^2+(y-k)^2 = r^2`

(where the center is known as
`(h,k)` and the radius, known as
`r`).

-Since you already have the center and the radius, use them for the equation of a circle:

Center:
`(-2,3)`

Radius:
`4`

`(x+2)^2+(y-3)^2 = 4^2`

After you have the equation of a circle, simplify the radius by the exponent
`2` :

`(x+2)^2+(y-3)^2 = 16`

So, you have found the equation of a circle.