Write the equation of a line perpendicular to y=3x-2 through the point (-5,8).

Question

asked Aug 11, 2021 128k views

1 Answer

Tangobravo · Answer 1 · 2021-08-17T03:26:31+0000

Answer:

y=-1/3x +29/3

Explanation

We know that the line perpendicular to a slope of 3 is it's opposite reciprocal. So the slope is -1/3. Substitute -5 as X and 8 as Y so you get:

8= -5/3x +b.

B= 29/3

That's your answer.