Question

A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape. (a) What is the probability that both grapes are green? (b) What is the probability that Henry eats a red grape then a green grape?

Answer 1

A. 28/253

B. 60/253

Step-by-step explanation

A. first step is to add all the grapes up which = 23

then you would put the

green grapes/ the total which would be 8/23

since henry ate one grape you would subtract 8-1 and then 23-1 and you would get 7 and 22

then you would put 7/22 and multiply 8/23 which gets you 28/253

B. first you put red grapes over total grapes which are 15/23

then,

you would do the green grapes which are 8/22

you would multiply 15/23 and 8/22 which = 60/253