asked 135k views
4 votes
h(t)=-5t^2+10t+3 is the height of a diver above the water, t seconds after the diver leaves the springboard. How high above the water is the springboard?

asked
User Ruth
by
7.4k points

1 Answer

2 votes

Answer:

3 units

Explanation:

So if we want to know how high the spring board is, this will need to be the time at which the diver is still at the top of the board, in this case t = 0 seconds.

So we will need to find h(0)

  • h(0) = 5(0)² + 10(0) + 3 = 0 + 0 + 3 = 3
answered
User Ntkachov
by
8.6k points
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