asked 14.6k views
4 votes
If sin theta <0 and tan theta >0 then:

2 Answers

3 votes

Note that
\tan\theta=(\sin\theta)/(\cos\theta). Thus, if
\sin\theta<0 and
\tan\theta>0, then we must have
\cos\theta<0 as well. The sine function is negative when
\theta lies in Quadrant III or IV, and the cosine function is negative when
\theta lies in Quadrant II or III. Thus, the two are both negative when
\theta lies in Quadrant III, or
\pi+2\pi n<\theta<(3\pi)/(2)+2\pi n for integer values of
n.

answered
User Heathobrien
by
9.0k points
4 votes

Answer:

Explanation:

If the sine is negative then theta must be in Quadrant III or Quadrant IV.

If the tangent is positive then theta must be in Quadrant I or III.

If both conditions must be satisfied, then we conclude that thera is in Quadrant III.

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