Question

The center of a circle is at (-5 12) and it has a radius of 16. what is the equation of the circle?

(x+5)^2+(y-12)^2=256
(x+5)^2+(y-12)^2=4
(x-5)^2+(y+12)^2=256
(x-5)^2+(y+12)^2=4​

Answer 1

(x+5)^2+(y-12)^2=256

Explanation:

Comparing the given (x+5)^2+(y-12)^2=256

to (x - h)^2 + (y - k)^2 = r^2,

we see that h must be -5, k must be 12 and r must be 16. This is the desired equation of the circle with center at (-5, 12) and radius 16.