Find the center and radius of the circle with equation (x + 3)^2 + (y + 6)^2 = 16

Question

asked May 12, 2021 121k views

2 Answers

TwDuke · Answer 1 · 2021-05-13T12:42:20+0000

Answer:

The center is at (h, k): (-3, -6) and the radius is r = 4.

Explanation:

Compare the given (x + 3)^2 + (y + 6)^2 = 16 with the standard equation of a circle (x - h)^2 + (y - k)^2 = r^2.

We can see immediately that h must be -3, k must be -6 and r must be 4.

The center is at (h, k): (-3, -6) and the radius is r = 4.