Question

A type of cell triples every hour. If there are 5 cells initially, which function can be used to

find the number of cells,c, at the end of t hours?
Oc(t) = 5(1)
O c(t) = 5(3)
Oc(t) = 5 + ( )'s
Oc(t) = 5+ (3)

Answer 1

T(t) = 5(3)(t)

Explanation:

There are 5 cells initially.

And it triple every hour.

So

T0 =5

T(t) = T0(3t)

Each cell has it's multipling factor because it's Will be multipling by 3 every hour

T(t) = 5(3)(t)