Question

A metal fragment is in a patient. The speed of sound in the tissue is 1450 m/s. The depth of the fragment is 0.265 m. What will be the time between the transducer emitting the sound and picking the sound echo up?

Answer 1

Time,
`t=1.82* 10^(-4)\ s`

Step-by-step explanation:

The speed of sound in the tissue is 1450 m/s and the depth of the fragment is 0.265 m.

It is required to find the time between the transducer emitting the sound and picking the sound echo up. The time taken by the sound is :

`t=(d)/(v)\\\\t=(0.265)/(1450)\\\\t=1.82* 10^(-4)\ s`

So, the time between the transducer emitting the sound and picking the sound echo up is
`1.82* 10^(-4)\ s`