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You have 2 ml of suspension of bacterial cells, and your task is to find out how many cells per ml are present in this suspension. You take 0.1 ml of the suspension and transfer into a tube with 9.9 ml of water. After mixing very thoroughly, you take 0.1 ml from the first dilution and transfer into a tube with 9.9 ml of water. After mixing very thoroughly, you take 0.2 ml from the second dilution, spread onto the surface of agar and incubate the plate at 37oC overnight. In the morning, you count 25 colonies on the plate. How many cells per ml were present in the original suspension

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Answer:

Step-by-step explanation:

Serial dilution for tube 2 is


=(0.1)/(0.1+9.9) * (0.1)/(0.1 * 9.9)


= (0.1)/(10) * (0.1)/(10) \\\\= (1)/(100) * (1)/(100) \\\\= (1)/(10^4)


CFU/ml=(colony)/( volume* dilution)


=(25)/(0.2* 10^-^4) \\\\=(25* 10^4)/(0.2) \\\\=(25 * 10^5)/(2) \\\\= 12.5 * 10^5\\\\= 1.25 * 10^6

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