Question

What is the center of a circle whose equation is x

Answer 1

(6, 1)

Explanation:

`{x}^(2) + {y}^(2) - 12x - 2y + 12 = 0 \\ equating \: it \: with \\ {x}^(2) + {y}^(2) + 2gx + 2fy + c= 0 \\we \: find \\ 2g = - 12 \implies \: g = - 6 \\ 2f = - 2 \implies \: f = - 1 \\ center \: of \: circle = ( - g \: \: - f) \\ center \: of \: circle = (6 \: \: 1)`