Question

Factorise using identity 4y^2 - 12yz+9z^2​

Answer 1

Explanation:

Identity used :

`\bold{ ({y}^(2) + {z}^(2)) = {y}^(2) + 2yz + {z}^(2) }`

`\implies \: {(2y)}^(2) - 2.2y.3z + {(3z)}^(2)`

so we got :

y = 2

z = 3

`{ \pink{ \bold{ \boxed{answer = (2y + 3z) {}^(2) }}}}`