Question

Find the third fourth and eleventh terms of the sequence described by the rule A(n)=-2+(n-1)(5)

Answer 1

8,13,48

Explanation:

Third = A(3) = -2 + (3-1)(5) = -2 + 10 = 8

Fourth = A(4) = -2 +(4-1)(5) = -2 + 15 = 13

Eleventh = A(11) = -2 + (11-1)(5) = -2 + 50 = 48