Answer:
0.27
Explanation:
To solve this problem, we will use Set Theory Approach to Probability. 
 
Let U = the Sample Space which consists of all possible tests. 
Of course U = {1,2,3 .... ,30} 
So, no elements in that. 
 
U = n = 30 
Let Q = the event bearing a multiple of 4 No winning ticket, and, 
R = the case that has the No. 19 winning ticket
∴ 
Q = { 4, 8, 12 , 16 , 20, 24 , 28} , and 
R = {19} , so that 
 Q ∩ R = ϕ 
P(Q ∩R ) = 0 
 As, n(Q) = 7 , n(R) = 1 , we have, 
 P (Q) = 
 =
 = 
 , and P (R) =
, and P (R) = 

P (Q∪R) = P(Q ) + P(R) − P(A∩B) = 
 +
 + 
 − 0 =
 − 0 = 

 ≅ 0.27 .