Question

The slope-intercept form of the equation of a line that passes through point (-2, -13) is y = 5x - 3. What is the point-

slope form of the equation for this line?
O y- 13 = 5(%- 2)
O y + 13 = 5(x + 2)
O y- 2 = 5(x- 13)
O y + 2 = 5(x+ 13)

Answer 1

`y = \stackrel{\stackrel{m}{\downarrow }}{5}x-3\qquad \impliedby \begin{array}c \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}`

well, what's the equation of a line whose slope is 5 and passes through (-2 , -13) ?

`(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-13})\qquad \qquad \stackrel{slope}{m}\implies 5 \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-13)}=\stackrel{m}{5}(x-\stackrel{x_1}{(-2)})\implies y+13=5(x+2)`