Question

Find the equation of the line that is parallel to y=5x+1 and passes through the point (10, -1)

Answer 1

The required equation is 5x-y-51 = 0

Explanation:

`the \: given \: equation \: is \\ y = 5x + 1 \\ 5x - y + 1 = 0 \\ the \: equation \: of \: the \: line \: \\ parallel \: to \: 5x - y + 1 = 0 \: \: is \\ 5x - y + k = 0 \\ since \: it \: passes \: through \: (10, - 1) \\ 5(10) - ( - 1) + k = 0 \\ 50 + 1 + k = 0 \\k = - 51 \\ the \: equation \: of \: the \: line \: parallel \: t o\: \\ 5x - y + 1 = 0 \: \: \: is \\ \: 5x - y - 51 = 0`

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