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(16x2y5 ÷ 4xy2 + 28xy) • 2y2 =

(16x2y5 ÷ 4xy2 + 28xy) • 2y2 =
asked 144k views
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(16x2y5 ÷ 4xy2 + 28xy) • 2y2 =

asked
User PGHE
by
8.1k points

1 Answer

3 votes

Answer:

8xy³(2y²+7)

Explanation:


( \frac{16 {x}^(2) * 2 {y}^(5) }{4x {y}^(2) } + 28xy) * 2 {y}^(2) \\ = (8x {y}^(3) + 28xy) * 2 {y}^(2) \\ = (4xy(2 {y}^(2) + 7)) * 2 {y}^(2) \\ = 8x {y}^(3) (2 {y}^(2) + 7)

answered
User PtQa
by
9.4k points
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