Question

a^3-b^3/(a-b)^3=73/3 what is a/b ik this is in biology but its impossible to get an answer in math someone please just help me solve this

Answer 1

Step-by-step explanation:

From the question,

`(a^(3) - b^(3) )/((a - b)^(3) )` =
`(73)/(3)`

Let the equation be equal to zero.

`(a^(3) - b^(3) )/((a - b)^(3) )` -
`(73)/(3)` = 0

`((a - b) *(a^(2) + ab + b^(2)) )/((a - b)^(3) )` -
`(73)/(3)` = 0

⇒
`((a^(2) + ab + b^(2)) )/((a - b)^(2) )` -
`(73)/(3)` = 0

Find the LCM,

`((a^(2) + ab + b^(2) )* 3 -73*(a - b)^(2) )/(3*(a - b)^(2) )` = 0

`(-70a^(2) + 149ab -70b^(2))/(3*(a^(2) -2ab + b^(2)) )` = 0

Factorizing the numerator and denominator gives,

`((10b - 7a)*(10a - 7b))/(3*(a - b)^(2) )` = 0

Multiply through by the denominator to have,

`((10b - 7a)*(10a - 7b))/(3*(a - b)^(2) )` × 3*
`(a - b)^(2)`= 0 × 3
`(a - b)^(2)`

⇒ (10b - 7a)*(10a - 7b) = 0

∴ -7a + 10b = 0 or -7b + 10a =

These gives the equation of a straight line; y = mx + b

Solving these equations graphically, we have;

For -7b + 10a = 0,

m = 1.429

a-intercept = 0.00000

b-intercept = -0.00000

For -7a + 10b = 0,

m = 0.700

a-intercept = -0.00000

b-intercept = 0.00000