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4 votes
Find three consecutive interferes whose sum is 96

1 Answer

7 votes

Answer:

31, 32, 33

Explanation:

x + x + 1 +x + 2 = 96

3x + 3 = 96

-3 -3

3x = 93

/3 /3

x = 31

31 is the first number, so since they’re consecutive, the second two numbers are 32 and 33.

answered
User Gautam Singh
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