Question

Help me please!!!!!!!!!!!!

Answer 1

Answer: B. 448.0 moles

Step-by-step explanation:

The balanced chemical equation is :

`2NBr_3+3NaOH\rightarrow N_2+3NaBr+3HOBr`

According to stoichiometry :

3 moles of
`NaOH` produce = 1 mole of
`N_2`

Thus 48.00 moles of
`NaOH` will produce =
`(1)/(3)* 48.00=16.00moles` of
`N_2`

Mass of
`N_2=moles* {\text {Molar mass}}=16.00moles* 28g/mol=448.0g`

Thus 448.0 g of
`N_2` will be produced from 48.00 moles of NaOH.