Question

what is the final molarity of a dilute solution of NaOH that is prepared by pipetting 5.00 mL of 7.00 M NaOH into a 100mL volumetric flask and diluting with water

Answer 1

`M_(diluted)=0.35M`

Step-by-step explanation:

Hello,

In this case, since in a dilution process the moles of the solute must remain unchanged, we use the volumes and molarities as shown below:

`M_(diluted)V_(diluted)=M_(concentrated)V_(concentrated)`

Clearly, the concentrated solution is 7.00M and the diluted solution is unknown, thus, the concentration of the diluted solution after the dilution to 100 mL is:

`M_(diluted)=(M_(concentrated)V_(concentrated))/(V_(diluted)) =(7.00M*5.00mL)/(100mL)\\ \\M_(diluted)=0.35M`

Best regards.