Question

If the pOH of a solution is 9.3, what is the [OH]?

a. 9.3 х 10-10
b. 5.0 x 10-10
с. 1.0
d. 47
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оооо

Answer 1

[OH] = b

`5.01 * {10}^( - 10) mol {dm}^( - 3)`

Step-by-step explanation:

pOH = -log [OH]

9.3 = -log [OH]

[OH] = 10^-9.3

[OH] = 5.01 × 10^-10 M