Question

Solve 11b^2-9=-68 using the square root method

Answer 1

b=i*
`\sqrt{(59)/(11) }` or -i*
`\sqrt{(59)/(11) }`

Explanation:

11b^2-9=-68

11b^2=-59

b^2=-59/11

b=i*
`\sqrt{(59)/(11) }` or -i*
`\sqrt{(59)/(11) }`

"i" in this case is an imaginary number, equal to
`√(-1\\)`

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