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What is the pressure, in KPa, of 2.00 mol of He in a 10.5 L container at 27.0 oC?

1 Answer

4 votes

Answer:

N= PV/RT (temperature in kelvin); ( r is .0821 when pressure is in atm & r is 8.314 when pressure is in Kpa)

2.00 = P x 10.0/ .0821 x 300

after solving i got 4.926 atm

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User Monnef
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