Question

What is the length of the diagonal of a poster board with dimensions 22 inches by 28 inches

Answer 1

Answer:35.6 inches

Explanation:

using Pythagoras principle we get

Length of diagonal=√(28^2+22^2)

Length of diagonal=√(28x28+22x22)

Length of diagonal=√(784+484)

Length of diagonal=√(1268)

Length of diagonal=35.6