Question

In AIJK, the measure of ZK=90° the measure of J=62 and KI = 2.7 feet. Find the

length of IJ to the nearest tenth of a foot.

Answer 1

IJ is 3.1 feet long, approximately.

Explanation:

In the image attached you can observe a representation of the problem.

Notice that we must find the hypothenuse of the right triangle. So, we need to use trigonometric reasons, because we have one angle and its opposite leg, that means we can use the sine reason.

`sin(62\°)=(2.7)/(x) \\x=(2.7)/(0.9) \\x\approx 3.1`

Therefore, IJ is 3.1 feet long, approximately.