Question

Given that [OH-] = 5.46x10^-9M

find the [H3O+] and state whether the solution is acidic or not and why?

Answer 1

• pOH=-log[OH-]
• pOH=-log[5.46×10^{-9}]
• pOH=-log5.46-log10^-9
• pOH=-0.74+9
• pOH=8.26

pH:-

• 14-pOH
• 14-8.26
• 5.74

It's acidic as pH<7

Now

• -log[H+]=5.74
• log[H+]=-5.74
• H+=10^{-5.74}
• H+=1.81×10^-6M