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What is the vertex of the quadratic function f(x)=(X-8)(x-2)

1 Answer

3 votes

Answer:

(5, -9)

Explanation:

This function has two zeros, which are {2, 8}. The x-coordinate of the vertex is midway from 2 to 8, or 5.

The y-coordinate is found by substituting 5 for x in f(x)=(X-8)(x-2):

f(5) = (5 - 8)(5 - 2) = -9

Thus, the vertex is at (5, -9).

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