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(1)=−10 h(2)=−2 h(n)=h(n−2)⋅h(n−1) ​ h(3)=

(1)=−10 h(2)=−2 h(n)=h(n−2)⋅h(n−1) ​ h(3)=
asked 233k views
1 vote
(1)=−10
h(2)=−2
h(n)=h(n−2)⋅h(n−1)
​
h(3)=

asked
User DMurdZ
by
7.8k points

2 Answers

2 votes

Answer:

6

Explanation:

answered
User Paul Stovell
by
8.4k points
4 votes

Answer:

20

Explanation:

h(3)=h(1)*h(2)=

(-10)*(-2)=

20

answered
User Raffaela
by
8.1k points
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