Question

What would be the coordinates at 315° if the coordinates at 135° are at (-square root 2/2, square root 2/2)?

Answer 1

We choose C

Explanation:

the coordinates at 135° are at (
`(-√(2) )/(2)`,
`(√(2) )/(2)` )

As we can see, the x coordinate of the point is negative and the y coordinate of it is positive.

So this point is located at the quadrant ii

From 135 ° to 315°, it is rotated 180°

=> Each coordinate (x,y) is changed to (-x,-y)

= (
`(√(2) )/(2)`,
`-(√(2) )/(2)` ) the new coordinate is located in quadrant iii

We choose C