Question

5. Find the molality if 2.3 moles of glucose is dissolved in 500.0 g of water.

Answer 1

The molality is 4.6
`(moles)/(kg)`

Step-by-step explanation:

Molality (m) is a concentration measurement that indicates the number of moles of solute that are dissolved in 1 kilogram of solvent.

The Molality of a solution is determined by the following expression:

`Molality=(number of moles of solute)/(kilograms of solvent)`

The molality is expressed in units (
`(moles)/(kg)`).

In this case:

• number of moles of solute: 2.3 moles
• kilograms of solvent: being 1 kg=1000 g, 500 g=0.5 kg

Replacing:

`Molality=(2.3 moles)/(0.5 kg)`

Solving:

Molality=4.6
`(moles)/(kg)`

The molality is 4.6
`(moles)/(kg)`