Question

Circle L is shown. Line segments K L and M L are radii. The length of K L is 12. Angle M L K is 60 degrees. Sector M L K with a 60 degree angle is shaded.

What is the area of the sector that is not shaded?


12Pi units squared

24Pi units squared

120Pi units squared

144Pi units squared

Answer 1

C

Explanation:

edge

Answer 2

`120\pi` square units

Explanation:

We are given that

Radius of circle=12 units

Angle MLK=60 degree

We have to find the area of sector that is not shaded.

Area of shaded sector MLK=
`(\theta)/(360)* \pi r^2`

Area of shaded sector MLK=
`(60)/(360)* \pi(12)^2=`24 square units

Area of whole circle=
`\pi r^2=\pi (12)^2=144\pi`square units

Area of sector that is not shaded =Area of whole circle-Area of shaded sector MLK=
`144\pi-24\pi`

Area of sector that is not shaded=
`120\pi` square units