Question

Consider the exponential function f(x) = 2(3x) and its graph.

On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases in quadrant 1. The equation of the function is y = f (x). The function crosses the y-axis at (0, 2).
The initial value of the function is.

The base of the function is.

The function shows exponential

Answer 1

The initial value of the function is 2

The base of the function is 3

The function shows exponential growth

Explanation:

Answer 2

The initial value of the function is 2

The base of the function is 3

The function shows exponential growth

Explanation:

f(x) = 2(3^x)

Exponential functions are those with the following equation:

y = a*b^x

where a ≠ 0, b > 0 and b ≠ 1 and x is a real number.

a is the y-intercept and b is the base.

The initial value of the function is the same as the y-intercept

If a is positive, the function growth. If a is negative, the function decay