Question

If a solution has a poh of 5.2 the [oh-] of the solution is

Answer 1

6x10^-6 M

Step-by-step explanation:

The relationship between pOH and [OH-] is

pOH = -log[OH-]

Solving this equation for [OH-] is

[OH-] = 10^-pOH

Plugging in the pOH makes

[OH-] = 10^-5.2

= 6.31x10^-6

Rounding to 1 sig fig since pOH and pH sig figs are only the number of decimals means to round to 1 sig fig or

6 x 10^-6 M