Question

The left end of a long glass rod 7.00 cmcm in diameter has a convex hemispherical surface 3.50 cmcm in radius. The refractive index of the glass is 1.60. The glass rod is immersed in oil (nn = 1.45). An object placed to the left of the rod on the rod's axis is to be imaged 1.15 mm inside the rod.

How far from the left end of the rod must the object be located to form the image?

Answer 1

n1/p + n2/q = (n2-n1)/R

1.45/p + 1.6/1.15 = (1.6 - 1.45)/0.035 (m)

1.45/p + 1.39 = 4.28

p = 0.50 m (50 cm)