Question

Two inductors are placed in a circuit in series with each other. Inductor 1 has an inductance of 3.5e-3 H and inductor 2 has an inductance of 1.38e-4 H. Anytime current is running through the inductors, what is the ratio of energy stored in inductor 1 compared to inductor 2? U1 is the energy in inductor 1 and U2 is the energy in inductor 2.

Answer 1

Ratio of energy stored in the inductor will be 2.536

Step-by-step explanation:

We have given two inductance
`L_1=3.5* 10^(-3)H`

`L_2=1.38* 10^(-4)H`

As inductors are connected in series so current will be same in both inductor

Energy stored in inductor is equal to
`(1)/(2)Li^2`

`U_1=(1)/(2)* 3.5* 10^(-3)* i^2......EQN 1`

Energy stored in second inductor

`U_2=(1)/(2)* 1.38* 10^(-4)* i^2......EQN 2`

Dividing equation 1 by equation 2

`(U_1)/(U_2)=((1)/(2)* 3.5* 10^(-3)i^2)/((1)/(2)* 1.38* 10^(-4)i^2)=2.536`