Question

Academic advising: In 2014, the Community College Survey of Student Engagement reported that 32% of the students surveyed rarely or never use academic advising services. Suppose that in reality, 42% of community college students rarely or never use academic advising services at their college. In a simulation we select random samples from this population. For each sample we calculate the proportion who rarely or never use academic advising services. If we randomly sample 200 students from this population repeatedly, the standard error is approximately 3.5%. Is it unusual to see 32% who rarely or never use academic advising services in one of these samples

Answer 1

= 0.0021

Since this probability is less than 0.05,

Yes , it is unusual to see 32% who really or never use academic advising services.

Step-by-step explanation:

Given,

Standard error = Sqrt( p( 1 -p) / n) = 0.035

Using normal approximation,

P( p<= p ) = P( Z < p - p / Sqrt( p( 1 -p) / n) )

= P( Z <= 0.32 - 0.42 / 0.035)

= P( Z < -2.8571)

= 1 - P( Z < 2.8571)

= 1 - 0.9979

= 0.0021

Since this probability is less than 0.05,

Yes , it is unusual to see 32% who really or never use academic advising services.