Question

The function E(d)=0.25d√ approximates the number of seconds it takes a dropped object to fall d feet on Earth. The function J(d)=0.64⋅E(d) approximates the number of seconds it takes a dropped object to fall d feet on Jupiter. How long (in seconds) does it take a dropped object to fall 50 feet on Jupiter? Round your answer to the nearest hundredth.

Answer 1

1.13 seconds

Explanation:

step 1

Find out how (in seconds) does it take a dropped object to fall 50 feet on Earth

we have

`E(d)=0.25√(d)`

we have

`d=50\ ft`

substitute

`E(50)=0.25√(50)\ sec`

step 2

Find out how (in seconds) does it take a dropped object to fall 50 feet on Jupiter

we have

`J(d)=0.64E(d)`

For

`d=50\ ft`

`J(50)=0.64E(50)`

Remember that

`E(50)=0.25√(50)\ sec`

substitute

`J(50)=0.64(0.25√(50))=1.13\ sec`