Question

How much energy is released when 33.8 g of water freezes? The heat of fusion for water is 6.02 kJ/mol.

Answer 1

11.29Kj

Step-by-step explanation:

1. find moles of 33.8g of water

Molar mass of H2O: 18.02g/Mol

33.8/18.02= 1.88mols

2. find energy

1.88 x 6.02= 11.29Kj