In ΔBCD, the measure of ∠D=90°, BD = 63, CB = 65, and DC = 16. What ratio represents the cosine of ∠B?

Question

asked Feb 3, 2021 118k views

2 Answers

Nikk · Answer 1 · 2021-02-09T09:04:55+0000

Answer:

$Cos \angle B=(63)/(13)$

Explanation:

-Given that ΔBCD is a right triangle with ∠D=90° as in the attached figure.

-The ratio of Cos of ∠B can be obtained using the right triangle identities:

$Cos \ \theta=(Adjacent)/(Hypotenuse)\\\\Cos \ B=(63)/(16)$

Hence, the cosine of ∠B can be represented by the ratios
$Cos \angle B=(63)/(13)$