Question

What is the value of the discriminant for the quadratic equation 0 equals X squared minus 4X +5 and how many number of real solutions does the equation have

Answer 1

Answer:-5

Explanation:

Answer 2

Discriminant: -4

No real solutions

Explanation:

You might remember this long, seemingly very hairy thing called the quadratic formula from earlier in algebra:

`x=(-b\pm√(b^2-4ac))/(2a)`

The discriminant of a quadratic equation of the form
`ax^2+bx+c=0` is that bit under the square root:
`b^2-4ac`. What does the discriminant tell us? Since we're taking its square root, we know that
`√(b^2-4ac)` is only real for non-negative values of
`b^2-4ac`. If
`b^2-4ac > 0`, we have two real roots, one for
`√(b^2-4ac)` and one for
`-√(b^2-4ac)`. If
`b^2-4ac = 0`, the function has a rational root, since the formula becomes

`x=(-b)/(2a)`

In your case, we have the equation
`x^2-4x+5`; here,
`a=1`,
`b=-4`, and
`c=5`, so our discriminant is
`(-4)^2-4(1)(5)=16-20=-4`. Since we'd have a negative under our square root in the quadratic formula, we have no real solutions.