Question

Calculate the molarity of a solution that contains 15.7 g of CaCO3 dissolved in enough water to make 275 mL of solution.

Answer 1

Molarity= 0.57M

Step-by-step explanation:

m=15.7 Molar mass Of CaCO3= 100 V=0.275dm3 C=?

n= m/M = 15.7/100= 0.157mole

n= C×V

0.157= C× 0.275

C= 0.57M