Question

A High Dive A 62.3 kg person jumps from rest off a 3.11 m-high tower straight down into the water. Neglect air resistance during the descent. She comes to rest 1.14 m under the surface of the water. Determine the magnitude of the average force that the water exerts on the diver. This force is nonconservative.

Answer 1

2276.1 N

Step-by-step explanation:

We are given that

Mass of person,m=62.3 kg

Initial velocity,u=0

Final velocity,v=0

Initial kinetic energy=Final kinetic energy=0

y=3.11 m

d=1.14 m

h=3.11+1.14=4.25 m

Final height, h'=0

Work done=Change in P.E energy

`-Fd=mg(h'-h)=-mg(h-h')`

`Fd=mg(4.25-0)`

`F=(62.3* 9.8* 4.25)/(1.14)`

`F=2276.1 N`