Question

I can’t figure out the answer

Answer 1

B

Explanation:

using the rule of radicals

`\sqrt{(a)/(b) }` ×
`\sqrt{(c)/(d) }` =
`\sqrt{(ab)/(cd) }` , then

`\sqrt{(3x)/(2) }` ×
`\sqrt{(x)/(6) }`

=
`\sqrt{(3x^2)/(12) }`

=
`\sqrt{(3x^2)/(3(4)) }`

=
`\sqrt{(x^2)/(4) }`

=
`(√(x^2) )/(√(4) )`

=
`(x)/(2)`