Question

Decomposition of NI3 produces nitrogen gas and iodine. How many grams of the reactant would be required to react completely to give 7.97g of the iodine.

Answer 1

Grams of the reactant would be required is 8.26 g

Step-by-step explanation:

Decomposition of NI3 is :

2 NI3 (s) --------------------> N2 (g)............... +..................... 3 I2 (g)

2 mol..................................1 mol.........................................3 mol

2 x 394.7 g/mol..............28 g/mol....................................3 x 253.8 g/mol

789.4 g...............................28 g...........................................761.4 g

From chemical equation it is cleared that

761.4 g of iodine is obtained from = 789.4 g of NI3

Therefore,

7.97 g of iodine is obtained from = 789.4 g x 7.97 g / 761.4 of NI3

= 6291.518 / 761.4 of NI3

= 8.26 g of NI3

Hence

Grams of the reactant would be required = 8.26 g