asked 177k views
4 votes
Louisville, with a temperature of -1°C, is cooler than Boise, with a temperature of 5°C. Write an inequality for the relationship of these temperatures.

asked
User Casbby
by
7.9k points

2 Answers

6 votes

Answer:

y ≥ x

Y = temperature of Boise

X = temperature of Louisville

Explanation:

Louisville temperature ( x ) = -1°c

Boise temperature ( y ) = 5°c

an inequality equation to represent this relationship will be y ≥ x this is because at any given time Louisville will always be cooler than Boise because its temperature is lower than Boise's temperature

An inequality equation is an equation used to represent two expressions or scenarios which are not equal to each other under given conditions

answered
User Martin Schultz
by
8.2k points
1 vote

Answer:

The answer is X < Y

Explanation:

Let Louisville's temperature be X and Boise's temperature be Y. According to the conditions given in the question where X is -1°C and Y is 5°C, the inequality should be written as X < Y.

I hope this answer helps.

answered
User Alexfigtree
by
8.2k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.