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How many 5-digit numbers contain at least one 3?

asked
User Sheery
by
7.6k points

1 Answer

0 votes

Answer:

37,512

Explanation:

Total # of 5 -digit numbers =9×104=90,000

Total # of 5 -digit numbers that do not contain 3=8×94=52,488

Total # of 5 -digit numbers that contain at least one 3=90,000−52,488=37,512

answered
User Ashakirov
by
8.1k points

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