Question

Find the vertex of y=(x-3)^2

Answer 1

The vertex form of parabola is,

`y=a(x-p)^2+q`

Where
`(p,q)` is vertex point.

In this case our parabola is given by,

`y=1(x-3)^2+0`

Hence the vertex is at
`(3,0)`.

Hope this helps.