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Celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in Celina's measurement?

Celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in Celina's measurement?
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Celina measured the height of a window frame as 5.55 feet, but the actual height was 6 feet. What is the percentage of error in Celina's measurement?

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User Ryvantage
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7.1k points

2 Answers

5 votes

Answer:

505

Explanation:

answered
User Cfrim
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8.2k points
3 votes
Make 5.55 a percent to get the answer
answered
User Steoates
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8.1k points
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